0=4y^2-14y+12

Solution for 0=4y^2-14y+12 equation:

0=4y^2-14y+12

We move all terms to the left:

0-(4y^2-14y+12)=0

We add all the numbers together, and all the variables

-(4y^2-14y+12)=0

We get rid of parentheses

-4y^2+14y-12=0

a = -4; b = 14; c = -12;
Δ = b2-4ac
Δ = 142-4·(-4)·(-12)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2}{2*-4}=\frac{-16}{-8}
=+2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2}{2*-4}=\frac{-12}{-8}
=1+1/2
$